答：x/(x-3) -2=m/(x-3)x/ (x-3) -m /(x-3)=2(x-m) /(x-3)=2x-m=2(x-3)x-m=2x-62x-x=6-mx=6-m>0并且x=6-m≠3所以：m<6并且m≠3
